A parallel plate capacitor consists of two square plates with dimensions L X L and a gap D. (2023)

physical Universidad


answer 1




Capacitor plate area

The distance between the plates is d

The capacitance C is given by

Assuming that V is the voltage

yes there if it duplicates


The electric field is given by

Dividing by 1 and 2 we get

Related questions

In the high jump, the athlete's kinetic energy can be converted into gravitational potential energy without the aid of a pole. Find the minimum velocity with which the athlete must rise from the ground to lift his center of mass 1.65 m and cross the bar at 0.75 m/s.


The minimum speed must be 5.74 m/s to lift your center of mass 1.65 m and pass the bar at 0.75 m/s.

given here,

v₁ - initial velocity = ?

h₁ - initial height = 0 meters

v2 - slutthastighed = 0,75 m/s

h2 - sluthøjde = 1,65 m

g - tyngdeceleration = 9.81 m/s²

The velocity can be calculated using the following formula,

Consider the quality,

Substituting the values ​​in the formula solves for V1

Therefore, the minimum speed must be 5.74 m/s to lift your center of mass 1.65 m and pass the bar at 0.75 m/s.

To learn more about kinetic energy,



The answer to your question is v₁ = 5.74 m/s



v₁ = ?

h₁ = 0 metros

v2 = 0,75 m/s

h2 = 1.65 meters

g = 9,81 m/s²


mgh₁ + 1/2mv₁² = mgh₂ + 1/2mv₂²

It does not consider quality (if we consider quality, it is canceled)

gh₁ + 1/2v₁² = gh₂ + 1/2v₁²


(9,81)(0) + 1/2v₁² = (9,81)(1,65) + 1/2(0,75)²


0 + 1/2v1² = 16.19 + 0.28

Solution for v₁

1/2v1² = 16.47

v₁² = 2(16,47)

v12 = 32,94


v1 = 5,74 m/s

To seven significant figures, the proton has a mass of 1.672623 x10^{-27} kg. Which of the following indicates that rounding is correct?




We get the mass of the proton.

There are seven significant figures.

We have to round up.

If we round to three significant figures

The thousands in a proton of a given mass is less than five, so the digits to the left of the thousands digit remain the same, and the thousands digit and the thousands digit to the right are replaced by zeros.

Therefore, the mass of a proton can be written as

Therefore, the mass of the proton is

At an instant, a particle is moving in the +x direction with a momentum of +8 kg m/s. During the next 0.13 seconds, a constant force acts on the particle, Fx=-7N, Fy=+5N. What is the magnitude of the particle's momentum at the end of this 0.13 second interval?



At the end of the 0.13 s time interval, the particle has a momentum of 7.12 kg m/s


The momentum of a particle is related to the force by the following equation:

Δp = F · Δt


Δp = change in momentum = final momentum - initial momentum

F = constant force.

Δt = time interval.

Let's calculate the x component of the impulse after 0.13 seconds:

Slutmomentum - 8 kg m/s = -7 N 0,13 s

Slutmomentum = -7 kg m/s² 0,13 s + 8 kg m/s

Slutmomentum = 7,09 kg m/s

Now let's calculate the y-component of the impulse vector after 0.13 seconds. Since the particle is not moving in the y-direction, the initial momentum in that direction is zero:

Slutmomentum = 5 kg m/s² 0,13 s

Slutmomentum = 0,65 kg m/s

The momentum vector will look like this:

p = (7,09 kg m/s, 0,65 kg m/s)

The magnitude of this vector is calculated as follows:

At the end of the 0.13 s time interval, the particle has a momentum of 7.12 kg m/s

Chameleons catch insects with their tongues, which can be extended rapidly. In a typical attack, the chameleon's tongue accelerates to a staggering 280 m/s2 m/s^2 for 20 ms {\rm ms} and then moves at a constant speed for another 30 ms {\rm ms}. How far does the tongue protrude during this total time of 50 ms {\rm ms} or 1/20 of a second?
Express your answers to two significant figures and include the appropriate units.



The length of the tongue is 23 cm.



The equation for the distance traveled is as follows:

x = x0 + v0 · t + 1/2 · a · t²


x = distance traveled in time t.

x0 = starting position.

v0 = initial velocity.

a = acceleration.

t = time.

Let's calculate how far the chameleon's tongue traveled in the first 20 milliseconds (0.020 seconds):

The initial position and velocity are zero (x0 = 0 and v0 = 0)

x = 1/2 · a · t²

x = 1/2 · 280 m/s² · (0,020 s)²

x = 0.056 meters

Now let's find out how much the tongue moves when moving at a constant speed. But first, let's calculate the velocity (v) of the tongue after the acceleration interval using the following equation:

v = v0 + a · t (v0 = 0)

v = 280 m/s² · 0.020 seconds

v = 5,6 m/s

Then the distance traveled at constant speed can be calculated:

x = v·t

x = 5,6 m/s 0,030 s

x = 0.17 meters

The extent of the tongue is 0.17 m + 0.056 m = 0.23 m = 23 cm.

A positively charged glass rod attracts object X. Net charge on object X: A. It can be zero or negative. B. It can be zero or a positive number. C. It must be negative. D. It must be a positive number. E. Must be zero.


Answer to


A positively charged glass rod attracts an object x. Therefore, the object x must be negatively charged or no charge.

This happens because opposite charges attract each other, or object x has no charge and a negative charge is induced in the glass rod as it approaches object x.

So option A is correct.

The slide runs across the top of the loop at twice the speed. What is the relationship between the normal force in Part A and gravity? What is the relationship between the normal force and the gravitational force? n/FG=2n/FG=2n/FG=3n/FG=3n/FG=4n/FG=4n/FG=5n/FG=5



n/(FG) = 3.


At the top of the loop, the normal force and the weight of the car are downward. Therefore, the total net power of the car is

According to Newton's second law, this force is equal to the centripetal force because the car is moving in a circle.

The critical speed is the lowest speed at which the car will not fall. Therefore, the normal force is zero at the critical velocity.

If the car is traveling at twice the critical speed, then

Finally there is the relationship between the normal force and gravity.

A force of 35 N is applied to the ball for 0.2 seconds. If the ball is initially at rest: a) What is the momentum of the ball?
b) What is the final momentum of the ball?


To solve this problem we will apply concepts related to the amount of movement and the moment of a body. Both are equivalent values, but they can be found using different expressions. Impulse is the product of force and time, while momentum is the product of mass and velocity. The results of these operations give equivalent units.

Part A) Heart rate can be calculated as follows


F = force

time change


Part B) At the same time, the momentum obeys the conservation of momentum, where:

initial impulse = final impulse

and the change in momentum is equal to the momentum, then


So there is no initial moment

How many times faster is the speed of sound in a liquid compared to the maximum amplitude of the particle's velocity?


Answer: 171500 times faster.

Explanation: First, that our fluid medium is air. The speed of sound in air is 343 m/s or 343,000 mm/s.

The velocity of the particles now represents the alternating average velocity of the particles in a medium like air in this case.

Air particles exposed to a standard sound pressure of 1 Pa have a maximum velocity amplitude of approx. 2mm/sec

Remember that the speed of sound in air, when converted to mm/s, is 343000 mm/s.

Find how many times faster than the maximum velocity of the particles in the air. We must divide this by the maximum velocity of the air particles, which is 2 mm/s.


=171500 times faster.

I think it's clear.

The scooter has a wheel diameter of 120 mm. What is the angular velocity of the wheels when the scooter moves at 6.00 m/s?


To solve this problem we will apply concepts related to angular movement, concepts related to linear movement. Linear velocity can be described by angular velocity as follows,


v = linear velocity

= angular velocity

r = radio

our values ​​are

Substituting to find the angular velocity we have,

Conversion of units to RPM we have

So, when the scooter is moving at 6.00 m/s, the angular velocity of the wheels is 955.41 rpm.

The speed of P waves in the earth's crust is about 7 km/s. The epicenter of a magnitude 7.6 earthquake is 280 kilometers from the nearest seismic station. How long does it take for the P wave to reach the station?



t = 40 seconds



P-wave speed = 7 km/s

Distance from the seismic station = 280 km

Time spent on the P wave = ?

we know,

distance = speed x time

t = 40 seconds

The time it takes for the P wave to reach the location is equal to 40 seconds.

An ambulance was heading towards the hospital at 108 km/h with a siren blaring at a constant 798 Hz. The sound bounced off the hospital and was picked up by the same ambulance. At what frequency can the ambulance hear the reflection's pitch change in addition to its own siren? The speed of sound on this day is 343 m/s. one. 1.06e+3Hz second 855 Hz 850 Hz 1.08e+3Hz 950 Hz


To solve this problem, we will apply concepts related to the Doppler effect. The Doppler effect is a physical phenomenon in which a sound source exhibits a distinctive change in wave frequency relative to the observer when the sound source is in motion. Mathematically, it can be described as

The meaning of each of these variables is,

detector speed

= the frequency of the wave emitted by the source

speed of sound source

v = speed of sound wave

= frequency received by the detector

replaced by,

So the correct choice is e.g. 950hz

Consider a positive charge Q and a point B that is twice as far from Q as point A. What is the relationship between the electric field strength at point A and the electric field strength at point B?


The ratio of the electric field at point A to the electric field at point B is 4.

gave us

A positive charge Q and point B is twice as far from Q as point A.

What is Coulomb's Law?

According to Coulomb's law, the electric force between two charged particles is inversely proportional to the square of the distance between them and directly proportional to the product of their charges.

We know that the electric field can be written as,

Combining the two equations we get

What is the relationship between the electric field?

we can write

Therefore, the ratio of the electric field intensity at point A to the electric field intensity at point B is 4.

More information about Coulomb's law:




The electric field is defined as the intensity of the electric field per unit charge, that is


Electricity can be obtained by Coulomb's law, which states that the electric force between charged particles is inversely proportional to the square of the distance between them and proportional to the product of their charges. Electricity can be expressed as


Substituting we get

Now let the electric field at point A be the electric field at point B, and let R be the distance of the charge from A:


The electric field ratio is

This means that at half the distance the electric field is four times stronger.

This is a computer program. Why is there an error between the computer value and the nominal value of R?



The difference is due to resistance tolerance.


In mathematical calculations, whether done by hand or in a computer program, the heat of a resistor is the nominal value written in its color code, so all calculations will give the same result, but resistors have a tolerance of A , expressed as the last band is usually 5%, 10%, 20%, even 1% on expensive precision resistors.

This tolerance or fluctuation in the value of the resistance is responsible for the discrepancy between the calculated value and the value measured with an instrument, multimeter.

Another source of error is also due to temperature changes in the circuit affecting the nominal value of the resistance, there is a very high resistance set that represents the change with temperature, they are only used in critical circuits due to their high cost

In short, the difference is due to the tolerances of the resistors.

When the balls are close but not touching, the following is observed: Balls B, C, and D are attracted to Ball A. Balls B and D have no influence on each other. Ball B is attracted to ball C. What is the state of charge of balls A, B, C, and D (positive, negative, or neutral)?



B and D are neutral. A and C have opposite charges.


Opposite charges attract and like charges repel. Also, neutral objects are attracted to charged objects, regardless of whether they are charged or charged.

- If the spheres B, C and D are attracted by A, then their charges are opposite to those of A or neutral.

- If balls B and D have no influence on each other, then both balls are neutral.

- If B is neutral and is attracted to C, then the charge on ball C is opposite to the charge on A.

Finally, B and D are neutral. A and C have opposite charges. The information in the question cannot be determined to be positive or negative.

A current of 202.0 mA transfers a charge of 56.0 C. Calculate the time it takes.



277 seconds


data data

  • Current (I): 202.0 mA = 202.0 × 10⁻³ A = 0.2020 A = 0.2020 C/s
  • Carried Charge (C): 56.0 Coulombs
  • Elapsed time (t): to be determined

We can find the elapsed time using the following expression.

i = carbon/tonne

t = C/I

t = 56,0 C/(0,2020 C/s)

t = 277 seconds

It took 277 seconds.

When the second student joins the first, the difference in liquid level in the left and right pistons is 40 cm. What is the mass of the other student?



Metro = 56,5 kg


When mass is added to one piston, the main pressure on the other piston changes. The calculated piston diameter is taken as 0.46 m.

Δm*g/area = p*g*Δh.....Eq1

How far apart must two 75.0 nC point charges (typical of electrostatics) be to create a force of 1.00 N between them?





Force between two charges = 1 N

Coulombs amor

where k=

use formula


use formula

Therefore, the distance between two charges =r=0.71 cm

Brewed coffee is often too hot to drink immediately. You can chill it with ice cubes, but that will dilute it. Or you can buy a device that cools coffee without diluting it: take a 200 aluminum cylinder out of the freezer and put it in a cup of hot coffee. q) If the cylinder is cooled to -20°C, which is a typical freezing temperature, and then a large cup of coffee (essentially water with a mass of 500g) is placed at 85°C, what is the temperature end of coffee? The answer is fig and the answer is 2 degrees Celsius.





  • a lot of aluminum,
  • The initial temperature of the aluminum cylinder,
  • much coffee,
  • the initial temperature of the coffee,
  • the specific heat of the coffee (assumed to be water),
  • specific heat of aluminum,

When the coffee is in contact with the aluminum cylinder, the heat given off by the coffee is equal to the heat obtained by the aluminum.


is the final temperature of the protocol.

A cat completes a full circle of the carousel in 6 seconds. The cats sit within a radius of 8.4 meters from the center. Find the minimum coefficient of friction that prevents the jack from slipping.


To solve this problem we will use the concept related to uniform circular motion from which we will obtain the speed of the object. From there we get the equilibrium equation, so the friction force must be equal to the centripetal force. We will delete the value of the coefficient of friction that we are looking for.

The speed of uniform circular motion can be described as


r = radio

T = points


To go from equilibrium to staying on the circle, friction must equal the centripetal force, so


coefficient of friction

N = force normal

m = time

v = speed

r = radio

Therefore, the value of the normal force is equal to the weight

rearrange to find the coefficient of friction


Therefore, the minimum coefficient of friction to prevent the jack from slipping is 0.9399.

A ball completely submerged in water is tied to the bottom with a string. The tension in the string is one quarter of the weight of the ball. What is the density of the sphere?



r = 800 kg/m3


Let the volume of the sphere = V

Density of the sphere = ρ

Density of water, ρ_w = 1000 Kg/m^3

The tension in the string is one quarter of the weight of the ball.

rope tension,

spheres and scales

T + weight = buoyancy

r = 800 kg/m3

The density of the ball is equal to 800 kg/m³

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